Operator's tricky Program 3

What will be output of the following program?

#include<stdio.h>

int main(){

    int i=1;

    i=2+2*i++;

    printf("%d",i);

    return 0;

}

Explanation

Output: 

Turbo C++ 3.0: 5

Turbo C ++4.5: 5

Linux GCC: 5

Visual C++: 5

Explanation:
i++ i.e. when postfix increment operator is used any expression the it first assign the its value in the expression the it increments the value of variable by one. So,

i = 2 + 2 * 1

i = 4

Now i will be incremented by one so i = 4 + 1 = 5