int abcdefghijklmnopqrstuvwxyz123456789=10;

#include<stdio.h>

int main(){

    int abcdefghijklmnopqrstuvwxyz123456789=10;

    int abcdefghijklmnopqrstuvwxyz123456=40;

    printf("%d",abcdefghijklmnopqrstuvwxyz123456);

    return 0;

}

Compilation error

Explanation: Only first 32 characters are significant in variable name. So compiler will show error: Multiple declaration of identifier abcdefghijklmnopqrstuvwxyz123456.

Blog Author: Vijay Kumar

Go to: Java Aptitude

class, public and private as variables

#include<stdio.h>

int main(){

    int class=150;

    int public=25;

    int private=30;

    class = class >> private - public;

    printf("%d",class);

    return 0;

}

Output: 4

Explanation: Variable name can be keyword of c++ in c.

Blog Author: Vijay Kumar

Go to: Java Aptitude

int max-val=100;

#include<stdio.h>

int main(){

    int max-val=100;

    int min-val=10;

    int avg-val;

    avg-val = max-val + min-val / 2;

    printf("%d",avg-val);

    return 0;

}

Compilation error

explanation: We cannot use special character – in the variable name.


Blog Author: Vijay Kumar

Go to: Java Aptitude

underscore as variable

#include<stdio.h>

int main(){

    int _=5;

    int __=10;

    int ___;

    ___=_+__;

    printf("%i",___);

    return 0;

}

output: 15

Explanation: Variable name can have only underscore.


Blog Author: Vijay Kumar

Go to: Java Aptitude

long int 1a=5l;

#include<stdio.h>

int main(){

long int 1a=5l;

printf("%ld",1a);

    return 0;

}

Compilation error

Invalid variable name. Variable name must star from either alphabet or underscore.

Blog Author: Vijay Kumar

Go to: Java Aptitude

int goto=5;

#include<stdio.h>

int main(){

int goto=5;

printf("%d",goto);

return 0;

}

Compilation error

Explanation:

Invalid variable name. goto is keyword in c. variable name cannot be any keyword of c language.

Blog Author: Vijay Kumar

Go to: Java Aptitude