#define

What will be output if you will compile and execute the following c code?

#define x 5+2

void main(){

    int i;

    i=x*x*x;

    printf("%d",i);

}

(A)	343
(B)	27
(C)	133
(D)	Compiler error
(E)	None of above

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Explanation:

As we know #define is token pasting preprocessor it only paste the value of micro constant in the program before the actual compilation start. If you will see intermediate file you will find:

test.c 1:

test.c 2: void main(){

test.c 3: int i;

test.c 4: i=5+2*5+2*5+2;

test.c 5: printf("%d",i);

test.c 6: }

test.c 7:

You can absorb #define only pastes the 5+2 in place of x in program. So,

i=5+2*5+2*5+2

=5+10+10+2

=27