if(printf("%d",printf("%d")))

    void main()

{

    while(1){

         if(printf("%d",printf("%d")))

             break;

         else

             continue;

    }

}

Answer:

Garbage values

Explanation:

The inner printf executes first to print some garbage value. The printf returns no of characters printed and this value also cannot be predicted. Still the outer printf  prints something and so returns a non-zero value. So it encounters the break statement and comes out of the while statement.

Blog Author: Vijay Kumar

Go to: Java Aptitude, C C++ Aptitude