for(;i>=0;i++) ;

main()

    {

       signed char i=0;

       for(;i>=0;i++) ;

       printf("%d\n",i);

    }

Answer

         -128

Explanation

Notice the semicolon at the end of the for loop. THe initial value of the i is set to 0. The inner loop executes to increment the value from 0 to 127 (the positive range of char) and then it rotates to the negative value of -128. The condition in the for loop fails and so comes out of the for loop. It prints the current value of i that is -128.

Blog Author: Vijay Kumar

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