#define clrscr() 100

#define clrscr() 100

main()

{

clrscr();

printf("%d\n",clrscr());

}

Answer:

100

Explanation:

Preprocessor executes as a seperate pass before the execution of the compiler. So textual replacement of clrscr() to 100 occurs.The input  program to compiler looks like this :

         main()

         {

              100;

              printf("%d\n",100);

         }

    Note:  100; is an executable statement but with no action. So it doesn't give any problem

Blog Author: Vijay Kumar

Go to: Java Aptitude