Slove (a+ !a + ~a + ++a)

    #include<stdio.h>

    int main()

{

    char a=250;

    int expr;

    expr= a+ !a + ~a + ++a;

    printf("%d",expr);
    return 0;

}

Output: -6

Explanation: char a = 250;

250 is beyond the range of signed char. Its corresponding cyclic value is: -6 (-128 to 127), 0 to 127 is occupied in first 1 to 250, then it remains 122. Now this 122 is occupied by -128 to -7 and remains -6.

So, a = -6

Consider on the expression:

expr= a+ !a + ~a + ++a;

Operator! , ~ and ++ have equal precedence. And it associative is right to left.

So, First ++ operator will perform the operation. So value a will -5

Now,

Expr = -5 + !-5 + ~-5 + -5

= -5 + !-5 + 4 – 5       

//(to solve ~-5 first make binary of 5 then subtract 1 and convert back to decimal.)

= -5 + 0 + 4 -5

= -6

Blog Author: Vijay Kumar

Go to: Java Aptitude