More about sizeof()

More about sizeof()

    #include<stdio.h>

    int main()

{

    double num=5.2;

    int  var=5;

    printf("%d\t",sizeof(!num));

    printf("%d\t",sizeof(var=15/2));

    printf("%d",var);
    return 0;

}

Output: 2       2          5

Explanation: sizeof(Expr)  operator always returns the an integer value which represents the size of the final value. Consider on the following expression: !num

=!5.2

=0

0 is int type integer constant and it size is 2

Consider on the following expression:

var = 15/2

=> var = 7

=> 7

7 is int type integer constant.

Any expression which is evaluated inside the sizeof operator its scope always will be within the sizeof operator. So value of variable var will remain 5 in the printf statement.

Blog Author: Vijay Kumar

Go to: Java Aptitude