Three same variables in program

    int i=10;

    main()

    {

     extern int i;

               {

         int i=20;

         {

          const volatile unsigned i=30;

          printf("%d",i);

         }

          printf("%d",i);

       }

    printf("%d",i);

    }

Answer:

30,20,10

Explanation:

'{' introduces new block and thus new scope. In the innermost block i is declared as,

    const volatile unsigned

which is a valid declaration. i is assumed of type int. So printf prints 30. In the next block, i has value 20 and so printf prints 20. In the outermost block, i is declared as extern, so no storage space is allocated for it. After compilation is over the linker resolves it to global variable i (since it is the only variable visible there). So it prints i's value as 10.

Blog Author: Vijay Kumar

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