printf("\n%c%c%c%c",c[ i ],*(c+i),*(i+c),i[c]);

main()

{

    char c[ ]="man";

    int i;

    for(i=0;c[ i ];i++)

    printf("\n%c%c%c%c",c[ i ],*(c+i),*(i+c),i[c]);

}

Answer:

            mmmm

             aaaa

            nnnn

Explanation:

c[i], *(i+c), *(c+i), i[c] are all different ways of expressing the same idea. Generally array name is the base address for that array. Here c is the base address. i is the index number/displacement from the base address. So, indirecting it with * is same as s[i]. i[s] may be surprising. But in the case of  C  it is same as s[i].


Blog Author: Vijay Kumar

Go to: Java Aptitude