j = i, j?(i,j)?i:j:j;

    main()

{

         int i=10,j=20;

    j = i, j?(i,j)?i:j:j;

         printf("%d %d",i,j);

}

Answer:

10 10

Explanation:

         The Ternary operator ( ? : ) is equivalent for if-then-else statement. So the question can be written as:

         if(i,j)

            {

if(i,j)

              j = i;

         else

             j = j;           

         }

       else

         j = j;      

Blog Author: Vijay Kumar

Go to: Java Aptitude, C C++ Aptitude

(i>2)?i++:i--;

    void main()

{

static int i;

while(i<=10)

(i>2)?i++:i--;

    printf(“%d”, i);

}

Answer:

         32767

Explanation:

Since i is static it is initialized to 0. Inside the while loop the conditional operator evaluates to false, executing i--. This continues till the integer value rotates to positive value (32767). The while condition becomes false and hence, comes out of the while loop, printing the i value.

Blog Author: Vijay Kumar

Go to: Java Aptitude, C C++ Aptitude

for (;i++=0;) printf(“%d”,i);

    main()

{

int i = 3;

for (;i++=0;) printf(“%d”,i);

}

Answer:

         Compiler Error: Lvalue required.

Explanation:

As we know that increment operators return rvalues and  hence it cannot appear on the left hand side of an assignment operation.

Blog Author: Vijay Kumar

Go to: Java Aptitude, C C++ Aptitude

while (strcmp(str1,str2)) (2)

    main()

{

char str1[] = {‘s’,’o’,’m’,’e’};

char str2[] = {‘s’,’o’,’m’,’e’,’\0’};

while (strcmp(str1,str2))

printf(“Strings are not equal\n”);

}

Answer:

“Strings are not equal”

“Strings are not equal”

….

Explanation:

If a string constant is initialized explicitly with characters, ‘\0’ is not appended automatically to the string. Since str1 doesn’t have null termination, it treats whatever the values that are in the following positions as part of the string until it randomly reaches a ‘\0’. So str1 and str2 are not the same, hence the result.

Blog Author: Vijay Kumar

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while (strcmp(“some”,”some\0”))

    main()

{

while (strcmp(“some”,”some\0”))

printf(“Strings are not equal\n”);

    }

Answer:

No output

Explanation:

Ending the string constant with \0 explicitly makes no difference. So “some” and “some\0” are equivalent. So, strcmp returns 0 (false) hence breaking out of the while loop.

Blog Author: Vijay Kumar

Go to: Java Aptitude, C C++ Aptitude